(2y)^2+(4y)^2+(10y)^2=0

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Solution for (2y)^2+(4y)^2+(10y)^2=0 equation:



(2y)^2+(4y)^2+(10y)^2=0
We add all the numbers together, and all the variables
16y^2=0
a = 16; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·16·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{32}=0$

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